An isosceles triangle has two equal sides, and the angles opposite those sides are also equal. These equal angles are often called the base angles.
Look for the two sides marked as equal. The angles across from them must have the same measure.
The three interior angles of any triangle add up to 180°. So if the two equal angles are each (x), and the third angle is known, write an equation such as:
[ x + x + \text{known angle} = 180 ]
Then solve for (x).
If one of the equal angles is given, the other equal angle has the same measure. If the vertex angle is known, subtract it from 180° and divide the remainder by 2.
Make sure:
If the vertex angle is 40°: [ \text{two equal angles} = 180 - 40 = 140 ] [ \text{each base angle} = 140 \div 2 = 70^ ]
So the key steps are: find the equal angles, use the 180° total, and verify the sum.
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